HFST - Helsinki Finite-State Transducer Technology API
version 3.7.1
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Two or more transducers do not have the same type. More...
#include <HfstExceptionDefs.h>
Additional Inherited Members | |
Public Member Functions inherited from HfstException | |
std::string | operator() (void) const |
Get the error message. More... | |
Two or more transducers do not have the same type.
This can happen if (1) the calling and called transducer in a binary operation, (2) two transducers in an HfstTransducerPair, (3) two consecutive transducers coming from an HfstInputStream or (4) two transducers in a function taking two or more transducers as arguments do not have the same type.
Thrown e.g. by HfstTransducer::disjunct(const HfstTransducer&) rules::two_level_if HfstTransducer(HfstInputStream&)
An example:
HfstTransducer foo("foo", SFST_TYPE); HfstTransducer bar("bar", FOMA_TYPE); foo.disjunct(bar); // an exception is thrown